Josephu 问题为：设编号为1，2，⋯ n的n个人围坐一圈，约定编号为k（1<=k<=n）的人从1开始报数，数到m 的那个人出列，它的下一位又从1开始报数，数到m的那个人又出列，依次类推，直到所有人出列为止，由此产生一个出队编号的序列。 ### 数组实现 ~~~ #include <stdio.h> #include <malloc.h> int Josephu(int n, int m) { int flag, i, j = 0; int *arr = (int *)malloc(n * sizeof(int)); for (i = 0; i < n; ++i) arr[i] = 1; for (i = 1; i < n; ++i) { flag = 0; while (flag < m) { if (j == n) j = 0; if (arr[j]) ++flag; ++j; } arr[j - 1] = 0; printf("第%4d个出局的人是：%4d号\n", i, j); } free(arr); return j; } int main( ) { int n, m; scanf("%d%d", &n, &m); printf("最后胜利的是%d号！\n", Josephu(n, m)); //system("pause"); return 0; } ~~~ ### 链表实现 ~~~ #include <stdio.h> #include <malloc.h> typedef struct Node { int index; struct Node *next; }JosephuNode; int Josephu(int n, int m) { int i, j; JosephuNode *head, *tail; head = tail = (JosephuNode *)malloc(sizeof(JosephuNode)); for (i = 1; i < n; ++i) { tail->index = i; tail->next = (JosephuNode *)malloc(sizeof(JosephuNode)); tail = tail->next; } tail->index = i; tail->next = head; for (i = 1; tail != head; ++i) { for (j = 1; j < m; ++j) { tail = head; head = head->next; } tail->next = head->next; printf("第%4d个出局的人是：%4d号\n", i, head->index); free(head); head = tail->next; } i = head->index; free(head); return i; } int main( ) { int n, m; scanf("%d%d", &n, &m); printf("最后胜利的是%d号！\n", Josephu(n, m)); //system("pause"); return 0; } ~~~