# C 程序：显示斐波那契数列 > 原文： [https://www.programiz.com/c-programming/examples/fibonacci-series](https://www.programiz.com/c-programming/examples/fibonacci-series) #### 在此示例中，您将学习显示前 n 个数字的斐波那契数列（由用户输入）。 要理解此示例，您应该了解以下 [C 编程](/c-programming "C tutorial")主题： * [C 编程运算符](/c-programming/c-operators) * [C `while`和`do...while`循环](/c-programming/c-do-while-loops) * [C `for`循环](/c-programming/c-for-loop) * [C `break`和`continue`](/c-programming/c-break-continue-statement) * * * 斐波那契数列是一个序列，其中下一项是前两项的和。 斐波那契数列的前两个项是 0，然后是 1。 ```c The Fibonacci sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21 ``` 访问此页面以了解有关[的斐波那契序列](https://www.mathsisfun.com/numbers/fibonacci-sequence.html)。 * * * ## 斐波那契数列（最多 n 个词） ```c #include <stdio.h> int main() { int i, n, t1 = 0, t2 = 1, nextTerm; printf("Enter the number of terms: "); scanf("%d", &n); printf("Fibonacci Series: "); for (i = 1; i <= n; ++i) { printf("%d, ", t1); nextTerm = t1 + t2; t1 = t2; t2 = nextTerm; } return 0; } ``` **输出** ```c Enter the number of terms: 10 Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ``` * * * ## 直到一定数目的斐波那契数列 ```c #include <stdio.h> int main() { int t1 = 0, t2 = 1, nextTerm = 0, n; printf("Enter a positive number: "); scanf("%d", &n); // displays the first two terms which is always 0 and 1 printf("Fibonacci Series: %d, %d, ", t1, t2); nextTerm = t1 + t2; while (nextTerm <= n) { printf("%d, ", nextTerm); t1 = t2; t2 = nextTerm; nextTerm = t1 + t2; } return 0; } ``` **输出** ```c Enter a positive integer: 100 Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ```