# C++ 程序：使用结构相加两个距离（以英寸和英尺为单位） > 原文： [https://www.programiz.com/cpp-programming/examples/inch-feet-structure](https://www.programiz.com/cpp-programming/examples/inch-feet-structure) #### 该程序需要两个距离（以英寸和英尺为单位），将其相加并在屏幕上显示结果。 要理解此示例，您应该了解以下 [C++ 编程](/cpp-programming "C++ tutorial")主题： * [C++ 结构](/cpp-programming/structure) * [C++ `if`，`if...else`和嵌套`if...else`](/cpp-programming/if-else) * * * * * * ## 示例：使用结构相加距离 ```cpp #include <iostream> using namespace std; struct Distance{ int feet; float inch; }d1 , d2, sum; int main() { cout << "Enter 1st distance," << endl; cout << "Enter feet: "; cin >> d1.feet; cout << "Enter inch: "; cin >> d1.inch; cout << "\nEnter information for 2nd distance" << endl; cout << "Enter feet: "; cin >> d2.feet; cout << "Enter inch: "; cin >> d2.inch; sum.feet = d1.feet+d2.feet; sum.inch = d1.inch+d2.inch; // changing to feet if inch is greater than 12 if(sum.inch > 12) { ++ sum.feet; sum.inch -= 12; } cout << endl << "Sum of distances = " << sum.feet << " feet " << sum.inch << " inches"; return 0; } ``` **输出** ```cpp Enter 1st distance, Enter feet: 6 Enter inch: 3.4 Enter information for 2nd distance Enter feet: 5 Enter inch: 10.2 Sum of distances = 12 feet 1.6 inches ``` 在此程序中，声明了一个包含两个数据成员（`feet`和`inch`）的结构`Distance`，以英寸-英尺系统存储距离。 在此，创建两个结构变量`d1`和`d2`来存储用户输入的距离。 并且，`sum`变量存储距离之和。 如果`sum`变量的`feet`的值大于 12，则`if..else`语句用于将英寸转换为英尺。