# Kotlin 程序：将二进制数转换为八进制，反之亦然 > 原文： [https://www.programiz.com/kotlin-programming/examples/binary-octal-convert](https://www.programiz.com/kotlin-programming/examples/binary-octal-convert) #### 在此程序中，您将学习使用 Kotlin 中的函数将二进制数转换为八进制数，反之亦然。 ## 示例 1：将二进制转换为八进制的程序 在此程序中，我们将首先将二进制数转换为十进制。 然后，十进制数字转换为八进制。 ```kt fun main(args: Array<String>) { val binary: Long = 101001 val octal = convertBinarytoOctal(binary) println("$binary in binary = $octal in octal") } fun convertBinarytoOctal(binaryNumber: Long): Int { var binaryNumber = binaryNumber var octalNumber = 0 var decimalNumber = 0 var i = 0 while (binaryNumber.toInt() != 0) { decimalNumber += (binaryNumber % 10 * Math.pow(2.0, i.toDouble())).toInt() ++i binaryNumber /= 10 } i = 1 while (decimalNumber != 0) { octalNumber += decimalNumber % 8 * i decimalNumber /= 8 i *= 10 } return octalNumber } ``` 运行该程序时，输出为： ```kt 101001 in binary = 51 in octal ``` 此转换发生为： ```kt Binary To Decimal 1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 0 * 21 + 1 * 20 = 41 Decimal to Octal 8 | 41 8 |5 -- 1 8 |0 -- 5 (51) ``` * * * ## 示例 2：将八进制转换为二进制的程序 在此程序中，八进制数首先从十进制到十进制。 然后，将十进制数转换为二进制数。 ```kt fun main(args: Array<String>) { val octal = 67 val binary = convertOctalToBinary(octal) println("$octal in octal = $binary in binary") } fun convertOctalToBinary(octalNumber: Int): Long { var octalNumber = octalNumber var decimalNumber = 0 var i = 0 var binaryNumber: Long = 0 while (octalNumber != 0) { decimalNumber += (octalNumber % 10 * Math.pow(8.0, i.toDouble())).toInt() ++i octalNumber /= 10 } i = 1 while (decimalNumber != 0) { binaryNumber += (decimalNumber % 2 * i).toLong() decimalNumber /= 2 i *= 10 } return binaryNumber } ``` 运行该程序时，输出为： ```kt 67 in octal = 110111 in binary ``` This conversion takes place as: ```kt Octal To Decimal 6 * 81 + 7 * 80 = 55 Decimal to Binary 2 | 55 2 | 27 -- 1 2 | 13 -- 1 2 | 6 -- 1 2 | 3 -- 0 2 | 1 -- 1 2 |0 -- 1 (110111) ``` 以下是等效的 Java 代码： [Java 程序：将二进制转换为八进制，反之亦然](/java-programming/examples/binary-octal-convert "Java Program to Convert Binary to Octal and vice-versa")