# Python 程序：检查闰年 > 原文： [https://www.programiz.com/python-programming/examples/leap-year](https://www.programiz.com/python-programming/examples/leap-year) #### 在该程序中，您将学习检查年份是否为闰年。 我们将使用嵌套`if...else`解决此问题。 要理解此示例，您应该了解以下 [Python 编程](/python-programming "Python tutorial")主题： * [Python 运算符](/python-programming/operators) * [Python `if...else`语句](/python-programming/if-elif-else) * * * 除世纪年份（以 00 结尾的年份）外，闰年可精确地除以 4。 只有将世纪完全除以 400，世纪年才是闰年。例如， ```py 2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year ``` ## 源代码 ```py # Python program to check if year is a leap year or not year = 2000 # To get year (integer input) from the user # year = int(input("Enter a year: ")) if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year)) else: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year)) ``` **输出** ```py 2000 is a leap year ``` 您可以在源代码中更改`year`的值，然后再次运行以测试该程序。