# 数组范围的平均值 > 原文： [https://www.geeksforgeeks.org/mean-range-array/](https://www.geeksforgeeks.org/mean-range-array/) 给定 n 个整数数组。 给出 q 个查询。 编写一个程序，在新行中为每个查询打印从 l 到 r 范围内的均值的下限值。 **示例**： ``` Input : arr[] = {1, 2, 3, 4, 5} q = 3 0 2 1 3 0 4 Output : 2 3 3 Here for 0 to 2 (1 + 2 + 3) / 3 = 2 Input : arr[] = {6, 7, 8, 10} q = 2 0 3 1 2 Output : 7 7 ``` **朴素的方法**：我们可以为每个查询 l 到 r 运行循环，并找到范围内元素的总和和数量。 此后，我们可以为每个查询打印均值下限。 ## C++ ```cpp // CPP program to find floor value // of mean in range l to r #include <bits/stdc++.h> using namespace std; // To find mean of range in l to r int findMean(int arr[], int l, int r) {     // Both sum and count are     // initialize to 0     int sum = 0, count = 0;     // To calculate sum and number     // of elements in range l to r     for (int i = l; i <= r; i++) {         sum += arr[i];         count++;     }     // Calculate floor value of mean     int mean = floor(sum / count);     // Returns mean of array     // in range l to r     return mean; } // Driver program to test findMean() int main() {     int arr[] = { 1, 2, 3, 4, 5 };     cout << findMean(arr, 0, 2) << endl;     cout << findMean(arr, 1, 3) << endl;     cout << findMean(arr, 0, 4) << endl;     return 0; } ```